We compute the newforms corresponding to elliptic curves over Q(Sqrt(2))
of conductor 11, and find there is only the one coming from Q.
> R<x> := PolynomialRing(IntegerRing());
> F := NumberField(x^2-2); OF := Integers(F);
> M := HilbertCuspForms(F, 11*OF);
> Dimension(M);
6
> time decomp := NewformDecomposition(NewSubspace(M)); decomp;
Time: 11.130
[*
New cuspidal space of Hilbert modular forms of dimension 1 over
Number Field with defining polynomial x^2 - 2 over the Rational Field
Level = Ideal of norm 121 generated by ( [11, 0] )
Weight = [ 2, 2 ],
New cuspidal space of Hilbert modular forms of dimension 5 over
Number Field with defining polynomial x^2 - 2 over the Rational Field
Level = Ideal of norm 121 generated by ( [11, 0] )
Weight = [ 2, 2 ]
*]
We look at the first few eigenvalues of the 1-dimension piece (at split primes).
> f := Eigenform(decomp[1]);
> primes := [P : P in PrimesUpTo(40,F) | IsOdd(Norm(P)) and IsPrime(Norm(P))];
> for P in primes do
> Norm(P), HeckeEigenvalue(f,P);
> end for;
7 -2
7 -2
17 -2
17 -2
23 -1
23 -1
31 7
31 7
Happily, they agree with the eigenvalues of the elliptic cusp form of conductor 11
over Q:
> fQ := Newforms(CuspForms(11))[1][1];
> for P in primes do
> p := Norm(P);
> p, Coefficient(fQ, p);
> end for;
7 -2
7 -2
17 -2
17 -2
23 -1
23 -1
31 7
31 7
The 5-dimensional piece conjecturally corresponds to an abelian variety
over F of dimension 5, which would be absolutely irreducible and have
real multiplication by the following field.
> K := HeckeEigenvalueField(decomp[2]);
> K;
Number Field with defining polynomial $.1^5 - 8*$.1^3 + 10*$.1 + 4 over F
> IsTotallyReal(K);
true